Lys van integrale

vanuit Wikipedia, die vrye ensiklopedie.

Integrasie is een van die hoofbewerkings van calculus. Vir differensiasie kan die eenvoudiger dele van 'n funksie maklik gedifferensieer word, wat differensiasie dan vergemaklik, maar dit kan egter nie met integrasie gedoen word nie. Vir gevalle waar daar met komplekse funksies gewerk word, is dit makliker om 'n lys van integrale byderhand te hou.

Vir die doeleindes van hierdie lys word K as arbitrêre-integrasiekonstante gebruik.

Inhoud

1 Reëls by die integreer van algemene funksies
2 Integrale van eenvoudige funksies
3 Verwysings
4 Aantekeninge

[wysig] Reëls by die integreer van algemene funksies

$\int af(x)\,dx = a\int f(x)\,dx \qquad\mbox{(}a \mbox{ konstant)}\,\!$

$\int [f(x) + g(x)]\,dx = \int f(x)\,dx + \int g(x)\,dx$

$\int f(x)g(x)\,dx = f(x)\int g(x)\,dx - \int \left[f'(x) \left(\int g(x)\,dx\right)\right]\,dx$

$\int [f(x)]^n f'(x)\,dx = {[f(x)]^{n+1} \over n+1} + K \qquad\mbox{(vir } n\neq -1\mbox{)}\,\!$

$\int {f'(x)\over f(x)}\,dx= \ln{\left|f(x)\right|} + K$

$\int {f'(x) f(x)}\,dx= {1 \over 2} [ f(x) ]^2 + K$

[wysig] Integrale van eenvoudige funksies

[wysig] Rasionale funksies

$\int \,{\rm d}x = x + K$

$\int x^n\,{\rm d}x = \frac{x^{n+1}}{n+1} + K\qquad\mbox{ mits }n \ne -1$

$\int {dx \over x} = \ln{\left|x\right|} + K$

$\int {dx \over {a^2+x^2}} = {1 \over a}\mbox{(bgtan)} {x \over a} + K$

[wysig] Irrasionale funksies

$\int {dx \over \sqrt{a^2-x^2}} = \sin^{-1} {x \over a} + K$

$\int {-dx \over \sqrt{a^2-x^2}} = \cos^{-1} {x \over a} + K$

$\int {dx \over x \sqrt{x^2-a^2}} = {1 \over a} \sec^{-1} {|x| \over a} + K$

[wysig] Logaritmes

$\int \ln {x}\,dx = x \ln {x} - x + K$

$\int \log_b {x}\,dx = x\log_b {x} - x\log_b {e} + K$

[wysig] Eksponensiaalfunksies

$\int e^x\,dx = e^x + K$

$\int a^x\,dx = \frac{a^x}{\ln{a}} + K$

[wysig] Trigonometriese funksies

$\int \sin{x}\, dx = -\cos{x} + K$

$\int \cos{x}\, dx = \sin{x} + K$

$\int \tan{x} \, dx = \ln{\left| \sec {x} \right|} + K$

$\int \cot{x} \, dx = -\ln{\left| \csc{x} \right|} + K$

$\int \sec{x} \, dx = \ln{\left| \sec{x} + \tan{x}\right|} + K$

$\int \csc{x} \, dx = -\ln{\left| \csc{x} + \cot{x}\right|} + K$

$\int \sec^2 x \, dx = \tan x +K$

$\int \csc^2 x \, dx = -\cot x + K$

$\int \sec{x} \, \tan{x} \, dx = \sec{x} + K$

$\int \csc{x} \, \cot{x} \, dx = - \csc{x} + K$

$\int \sin^2 x \, dx = \frac{1}{2}(x - \sin x \cos x) + K$

$\int \cos^2 x \, dx = \frac{1}{2}(x + \sin x \cos x) + K$

$\int \sec^3 x \, dx = \frac{1}{2}\sec x \tan x + \frac{1}{2}\ln|\sec x + \tan x| + K$

$\int \sin^n x \, dx = - \frac{\sin^{n-1} {x} \cos {x}}{n} + \frac{n-1}{n} \int \sin^{n-2}{x} \, dx$

$\int \cos^n x \, dx = \frac{\cos^{n-1} {x} \sin {x}}{n} + \frac{n-1}{n} \int \cos^{n-2}{x} \, dx$

$\int \mbox{bgtan}{x} \, dx = x \, \mbox{bgtan}{x} - \frac{1}{2} \ln{\left| 1 + x^2\right|} + K$

[wysig] Hiperboliese funksies

$\int \sinh x \, dx = \cosh x + K$

$\int \cosh x \, dx = \sinh x + K$

$\int \tanh x \, dx = \ln| \cosh x | + K$

$\int \mbox{csch}\,x \, dx = \ln\left| \tanh {x \over2}\right| + K$

$\int \mbox{sech}\,x \, dx = \mbox{bgtan}(\sinh x) + K$

$\int \coth x \, dx = \ln| \sinh x | + K$

$\int \mbox{sech}^2 x\, dx = \tanh x + K$

[wysig] Inverse hiperboliese funksies

$\int \sinh ^{-1} x \, dx = x \sinh ^{-1} x - \sqrt{x^2+1} + K$

$\int \cosh ^{-1} x \, dx = x \cosh ^{-1} x - \sqrt{x^2-1} + K$

$\int \tanh ^{-1} x \, dx = x \tanh ^{-1} x + \frac{1}{2}\log{(1-x^2)} + K$

$\int \mbox{csch} ^{-1} \,x \, dx = x \mbox{csch} ^{-1} x + \log{\left[x\left(\sqrt{1+\frac{1}{x^2}} + 1\right)\right]} + K$

$\int \mbox{sech} ^{-1} \,x \, dx = x \mbox{sech} ^{-1} x - \mbox{bgtan}{\left(\frac{x}{x-1}\sqrt{\frac{1-x}{1+x}}\right)} + K$

$\int \coth ^{-1} x \, dx = x \coth ^{-1} x+ \frac{1}{2}\log{(x^2-1)} + K$

[wysig] Bepaalde integrale sonder geslote-vorm afgeleides

$\int_0^\infty{\sqrt{x}\,e^{-x}\,dx} = \frac{1}{2}\sqrt \pi$

$\int_0^\infty{e^{-x^2}\,dx} = \frac{1}{2}\sqrt \pi$ (die Gaussiese integraal)

$\int_0^\infty{\frac{x}{e^x-1}\,dx} = \frac{\pi^2}{6}$

$\int_0^\infty{\frac{x^3}{e^x-1}\,dx} = \frac{\pi^4}{15}$

$\int_0^\infty\frac{\sin(x)}{x}\,dx=\frac{\pi}{2}$

$\int_0^\frac{\pi}{2}\sin^n{x}\,dx=\int_0^\frac{\pi}{2}\cos^n{x}\,dx=\frac{1 \cdot 3 \cdot 5 \cdot \cdots \cdot (n-1)}{2 \cdot 4 \cdot 6 \cdot \cdots \cdot n}\frac{\pi}{2}$ (mits n `n ewe heelgetal en $\scriptstyle{n \ge 2}$ )

$\int_0^\frac{\pi}{2}\sin^n{x}\,dx=\int_0^\frac{\pi}{2}\cos^n{x}\,dx=\frac{2 \cdot 4 \cdot 6 \cdot \cdots \cdot (n-1)}{3 \cdot 5 \cdot 7 \cdot \cdots \cdot n}$ (mits n `n onewe heelgetal en $\scriptstyle{n \ge 3}$ )

$\int_0^\infty\frac{\sin^2{x}}{x^2}\,dx=\frac{\pi}{2}$

$\int_0^\infty x^{z-1}\,e^{-x}\,dx = \Gamma(z)$ (waar

Γ(z)

die Gamma funksie is)

$\int_{-\infty}^\infty e^{-(ax^2+bx+c)}\,dx=\sqrt{\frac{\pi}{a}}\exp\left[\frac{b^2-4ac}{4a}\right]$ (waar

exp[u]

die eksponensiaalfunksie

e u

is.)

$\int_{0}^{2 \pi} e^{x \cos \theta} d \theta = 2 \pi I_{0}(x)$ (waar

I 0 (x)

die gewysigde Bessel funksie van die eerste tipe is.)

$\int_{0}^{2 \pi} e^{x \cos \theta + y \sin \theta} d \theta = 2 \pi I_{0} \sqrt{x^2 + y^2}$

$\int_{-\infty}^{\infty}{(1 + x^2/\nu)^{-(\nu + 1)/2}dx} = \frac { \sqrt{\nu \pi} \ \Gamma(\nu/2)} {\Gamma((\nu + 1)/2))}\,$ ( $\nu > 0\,$ .

$\int_a^b{f(x)\,dx} = (b - a) \sum\limits_{n = 1}^\infty {\sum\limits_{m = 1}^{2^n - 1} {\left( { - 1} \right)^{m + 1} } } 2^{ - n} f(a + m\left( {b - a} \right)2^{-n} )$

[wysig] Verwysings

Stewart, J. (2003). Single Variable Calculus. (5th ed.). Belmont, USA: Thomson Learning.
Groenewald, G.J., Hitge, M. (2005). Analise II Studiegids vir WISK121A. Potchefstroom: Noordwes-Universiteit.
Jordan, D.W., Smith, P. (2002). Mathematical techniques: An introduction for the engineering, physical and mathematical sciences. USA: Oxford University Press.

[wysig] Aantekeninge

Sien ook Lys van afgeleides
Hierdie artikel is 'n vertaling van die Engelse Wikipedia artikel Table of integrals

Kategorieë: Lyste • Wiskunde

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