South African general election, 1989
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The 1989 South African general election was South Africa's last national race-based parliamentary election. Although it still won an absolute majority, the National Party (NP) suffered an electoral setback, winning only 48% of the popular vote and 103 of the seats in parliament.
The official opposition Conservative Party (CP), who opposed any form of powersharing with other race groups, remained the official opposition with 41 seats and gained 31% of the votes.
Before the elections the liberal Progressive Federal Party (PFP) had dissolved itself in favor of the Democratic Party (DP), which went on to take 34 seats.
6 September 1989, House of Assembly Election
- Registered Voters: 3,120,104
- Total Votes (Voter Turnout): 2,167,929 (69.48%)
- Invalid/Blank Votes: 10,336
- Total Valid Votes: 2,157,593
| Party | Seats | Percent | Number of Votes |
| National Party | 103 | 48.19% | 1,039,704 |
| Conservative Party | 41 | 31.52% | 680,131 |
| Democratic Party | 34 | 20.00% | 431,444 |
| Herstigte Nasionale Party | 0 | 0.25% | 5,416 |
| TOTAL | 178 | - | 2,157,593 |
- The White Chamber of Parliament had 178 members, 166 of whom were directly elected (including a seat from Walvis Bay, which was added in 1981) with 8 Members indirectly elected by the directly elected members on the basis of proportional representation and 4 nominated by the State President (one from each province). Source [1]
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