1967 NBA Playoffs
From Wikipedia, the free encyclopedia
The 1967 NBA Playoffs was the postseason tournament of the National Basketball Association's 1966-1967 season. The tournament concluded with the Eastern Conference champion Philadelphia 76ers defeating the Western Conference champion San Francisco Warriors, four games to two in the NBA Finals.
It was the 76ers' second NBA championship in franchise history; their first title had come in 1955 as the Syracuse Nationals.
The Boston Celtics were denied the chance to win their ninth consecutive championship, though they would win the title in the following two seasons.
The expansion Chicago Bulls made the playoffs in their debut season, and the New York Knicks returned to the postseason for the first time since 1959. As of 2006, the seven-year gap between playoff appearances is the longest such gap in Knicks franchise history.
The 1967 NBA playoffs marked a change in playoff format for the league; every tournament since 1955 had given the top-ranked team in each conference a first-round bye, but starting this season the NBA upped the number of playoff teams from six to eight and removed the bye privilege from the regular-season conference champion.
| Division Semifinals | Division Finals | NBA Finals | |||||||||||
| 1 | San Francisco | 3 | |||||||||||
| 3 | L.A. Lakers | 0 | |||||||||||
| 1 | San Francisco | 4 | |||||||||||
| Western Division | |||||||||||||
| 2 | St. Louis | 2 | |||||||||||
| 4 | Chicago | 0 | |||||||||||
| 2 | St. Louis | 3 | |||||||||||
| W1 | San Francisco | 2 | |||||||||||
| E1 | Philadelphia | 4 | |||||||||||
| 1 | Philadelphia | 3 | |||||||||||
| 3 | Cincinnati | 1 | |||||||||||
| 1 | Philadelphia | 4 | |||||||||||
| Eastern Division | |||||||||||||
| 2 | Boston | 1 | |||||||||||
| 4 | New York | 1 | |||||||||||
| 2 | Boston | 3 | |||||||||||
